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목차
PROBLEMS
2.12.* An open-ended can 1 ft long is originally full of air at 70℉. The can is now immersed in water, as shown in Fig. 2.23. Assuming that the air stays at 70℉ and behaves as ideal gas, how high will the water rise in the can?
2.24.* In the hydraulic lift in Fig. 2.24. the total mass of car, rack, and piston 1800 kg. The piston has a cross-sectional area of 0.2 m^2. What is the pressure in the hydraulic fluid in the cylinder if the car is not moving?
2.42. Currently, recreational balloons are not filled with hydrogen or helium but with hot air; the pilot has a small propane burner to heat the air in the balloon.
2.45. A 150-lb drunkard falls in a vat of whiskey. Whiskey has SG=0.92, whereas the drunkard has SG =0.99. The drunkard
2.52.* The tow thank in Fig. 2.26 are connected through a mercury manometer. What is the relation between ∆z and ∆h ?
2.69. The rectangular tank Fig 2.33 is sitting on a cart. We now slowly accelerate the cart. What is the maximum acceleration we can give the cart with out having the fluid spill over the edge of the tank?
2.12.* An open-ended can 1 ft long is originally full of air at 70℉. The can is now immersed in water, as shown in Fig. 2.23. Assuming that the air stays at 70℉ and behaves as ideal gas, how high will the water rise in the can?
2.24.* In the hydraulic lift in Fig. 2.24. the total mass of car, rack, and piston 1800 kg. The piston has a cross-sectional area of 0.2 m^2. What is the pressure in the hydraulic fluid in the cylinder if the car is not moving?
2.42. Currently, recreational balloons are not filled with hydrogen or helium but with hot air; the pilot has a small propane burner to heat the air in the balloon.
2.45. A 150-lb drunkard falls in a vat of whiskey. Whiskey has SG=0.92, whereas the drunkard has SG =0.99. The drunkard
2.52.* The tow thank in Fig. 2.26 are connected through a mercury manometer. What is the relation between ∆z and ∆h ?
2.69. The rectangular tank Fig 2.33 is sitting on a cart. We now slowly accelerate the cart. What is the maximum acceleration we can give the cart with out having the fluid spill over the edge of the tank?
본문내용
PROBLEMS
2.12.* An open-ended can 1 ft long is originally full of air at 70℉. The can is now immersed in water, as shown in Fig. 2.23. Assuming that the air stays at 70℉ and behaves as ideal gas, how high will the water rise in the can?
≪ 그 림 ≫
P_water=P_atm+P_(water in can)
P_water=P_atm+ρ_water g∙(10[ft]-h_water )
P_atm 1[ft]=P_Air (10[ft]-h_water )
P_Air=(P_atm 1[ft])/((1[ft]-h_water ) )
P_water=P_Air
≪ … 중 략 … ≫
2.42. Currently, recreational balloons are not filled with hydrogen or helium but with hot air; the pilot has a small propane burner to heat the air in the balloon. If the balloon is a sphere 20 m in diameter, and if the total weight of balloon, pilot, passenger compartment, propane burner, propane tank, ropes ect. is 200kg, what average temperature must the air in the balloon have to just barely lift the balloon? Assume that the air inside and outside the balloon both have atmosphere pressure and have equal molecular weights, 29 gm/gmol. (The latter is slightly inaccurate because of the products of combustion inside the balloon; this inaccuracy is small)
1. Total Equation
F_(total weight)=V_balloon (ρ_air-ρ_gas )g
F_(total weight)/(V_balloon∙g)=(ρ_air-ρ_gas )
ρ_gas=ρ_air-F_(total weight)/(V_balloon∙g)
ρ_gas=ρ_air-F_(total weight)/(4/3 π(1/2 d)^3∙g)
2.12.* An open-ended can 1 ft long is originally full of air at 70℉. The can is now immersed in water, as shown in Fig. 2.23. Assuming that the air stays at 70℉ and behaves as ideal gas, how high will the water rise in the can?
≪ 그 림 ≫
P_water=P_atm+P_(water in can)
P_water=P_atm+ρ_water g∙(10[ft]-h_water )
P_atm 1[ft]=P_Air (10[ft]-h_water )
P_Air=(P_atm 1[ft])/((1[ft]-h_water ) )
P_water=P_Air
≪ … 중 략 … ≫
2.42. Currently, recreational balloons are not filled with hydrogen or helium but with hot air; the pilot has a small propane burner to heat the air in the balloon. If the balloon is a sphere 20 m in diameter, and if the total weight of balloon, pilot, passenger compartment, propane burner, propane tank, ropes ect. is 200kg, what average temperature must the air in the balloon have to just barely lift the balloon? Assume that the air inside and outside the balloon both have atmosphere pressure and have equal molecular weights, 29 gm/gmol. (The latter is slightly inaccurate because of the products of combustion inside the balloon; this inaccuracy is small)
1. Total Equation
F_(total weight)=V_balloon (ρ_air-ρ_gas )g
F_(total weight)/(V_balloon∙g)=(ρ_air-ρ_gas )
ρ_gas=ρ_air-F_(total weight)/(V_balloon∙g)
ρ_gas=ρ_air-F_(total weight)/(4/3 π(1/2 d)^3∙g)
- 가격1,200원
- 페이지수8페이지
- 등록일2015.04.22
- 저작시기2013.9
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- 자료번호#964807
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